Iron metal can beproduced by reducing iron(III) oxide with hydrogen: Fe 2 O 3 (s

Question

8. Iron metal can beproduced by reducing iron(III) oxide with hydrogen:

Fe2O3(s) + 3 H2 (g) 2Fe(s) + 3 H2O (g)
H° = +98.8kJ; S° = +141.5 J/K
Is this reaction spontaneousunder standard-state conditions at 25°C? YES or NO Calculate G°using H° and S° values  
Calculate G°using G°f values  
At what temperaturewill the reaction become spontaneous?  
Does the reversereaction become spontaneous at higher temperatures or lowertemperatures? Explain.  

Fe2O3(s) + 3 H2 (g) 2Fe(s) + 3 H2O (g)
H° = +98.8kJ; S° = +141.5 J/K
Is this reaction spontaneousunder standard-state conditions at 25°C? YES or NO

Explanation / Answer

We Know that :         The given Reactionis :         Fe2O3(s) + 3H2 (g) <-----> 2 Fe(s) + 3 H2O(g)        We Know that:         According to Gibb'sEquation :            G = H - T S                    = 98.8 x 103 J   - 298 K x 141.5 J / K                      = 56633J          The Reactionis Non- Spontaneous under the given Condition.         G = Gproducts - Greactants                  = 2 x 0 + 3 x -228.57 ) KJ - [ -742.2 + 3 x 0 ] KJ                   = + 56.49 KJ       At equilibrium G = 0         T = H / S             = 98.8 x 103   J / 141.5 J /K             = 698.2332 K         If the temperatureof the Reaction is greater than 698.2332 K the Reaction isSpontaneous.        The Reverse Reaction isSpontaneous is lower temperature as the Forward Reaction isEndothermic which       accompained with theabsorption of heat the Reverse Reaction is accompained by theevolution of heat so it       will be spontaneous under lowertemperature conditions.                 We Know that:         According to Gibb'sEquation :            G = H - T S                    = 98.8 x 103 J   - 298 K x 141.5 J / K                      = 56633J          The Reactionis Non- Spontaneous under the given Condition.         G = Gproducts - Greactants                  = 2 x 0 + 3 x -228.57 ) KJ - [ -742.2 + 3 x 0 ] KJ                   = + 56.49 KJ       At equilibrium G = 0         T = H / S             = 98.8 x 103   J / 141.5 J /K             = 698.2332 K         If the temperatureof the Reaction is greater than 698.2332 K the Reaction isSpontaneous.        The Reverse Reaction isSpontaneous is lower temperature as the Forward Reaction isEndothermic which       accompained with theabsorption of heat the Reverse Reaction is accompained by theevolution of heat so it       will be spontaneous under lowertemperature conditions.                  = 2 x 0 + 3 x -228.57 ) KJ - [ -742.2 + 3 x 0 ] KJ                   = + 56.49 KJ       At equilibrium G = 0         T = H / S             = 98.8 x 103   J / 141.5 J /K             = 698.2332 K         If the temperatureof the Reaction is greater than 698.2332 K the Reaction isSpontaneous.        The Reverse Reaction isSpontaneous is lower temperature as the Forward Reaction isEndothermic which       accompained with theabsorption of heat the Reverse Reaction is accompained by theevolution of heat so it       will be spontaneous under lowertemperature conditions.         

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.