part A says: When placed 1.12 m apart, the force each exerts on the other is 11.

Question

part A says:

When placed 1.12 m apart, the force each exerts on the other is 11.4 N and is repulsive. What is the charge on each?
Enter your answers in ascending order separated by comma.

and part B says:

What if the force were attractive?
Enter your answers in ascending order separated by comma.

Explanation / Answer

total charge q + q' = 93 uC = 93 *10^-6 C -----( 1) separation r = 1.12 m force F = 11.4 N we know F = Kqq' / r^ 2 from this qq' = Fr^ 2/ K where K = coulomb's constant = 8.99*10^9 Nm^ 2/ C^ 2 plug the values we get qq' = 1.59*10^-9 ----( 2) we know q- q ' = sqrt [ (q+q')^ 2-4qq'] = 47.8*10^-6 C ---( 2) [eq( 1)+eq( 2) ] / 2 ==> q = 70.4 * 10^-6 C and q ' = ( q+ q') - q = 22.6* 10^-6 C So, charges are 22.6 uC , 70.4 uC (B). if the force is attractive ,one is positive and second is negative. So, q q' = -1.59*10^-9 using this you find charges q , q'

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.