part 1 of2 Consider two cylindrical conductors made out of the same material (i.

Question

part 1 of2 Consider two cylindrical conductors made out of the same material (i.e. they have the same density of charge carriers and the same resistivity). part 2 of2 T2 4V1 , and P2 = of the magnitudes If 12-311 , r2 = 2r1 , ½ What is the ratioof the resistances? Ud,2 Ud,1 what is the ratio of the drift velocities? Vd,2 Ud,1 Ud,2 1 Vd,13 Vd,2 vd,1 64 Ud,2 4 Vd,13 2. 12 R1 64 R1 3 4 R1 2 R2 16 R1 3 4 Ud,2 Ud,1 Vd,2 vd,116 Ud,216 Ud,1 6. 2 R1 16 R2 64 R1 3 R2 3 8. 'd264 9 Ud,1 Ud,2 1 Vd,12 Vd,2 Ud,1 10. H2 R1 3

Explanation / Answer

2)We know that,

R = rho L/A

R1 = rho l1/ pi r1^2

R2 = rho (3l1)/pi 4 r^2

R2/R1 = rho 3 l1/ pi 4r^2 x pi r^2/ rho l1

R2/r1 = 3/4

Hence, (9) R2/R1 = 3/4

1)We know that the drift velocity is given by:

Vd = I/n e A = V/ n e A R = V/ n e A rho L/A = V/n e rho L

Vd1 = V1/n e rho l1

Vd2 = 4 V1/ n e rho 3 l1

Vd2/Vd1 = 4 V1/3 n e rho l1 x n e rho l1/ V1 = 4/3

Hence, (4)Vd,2/Vd,1 = 4/3

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