part 1) Voice over IP (VoIP) Given the attached image, and:h Host A converts ana

Question

part 1)

Voice over IP (VoIP)

Given the attached image, and:h

Host A converts analog to digital at a = 48 Kbps

Link transmission rate R = 3.7 Mbps

Host A groups data into packets of length L = 113 bytes

Distance to travel d = 774.6 km

Propagation speed s = 2.5 x 108 m/s

Host A sends each packet to Host B as soon as it gathers a whole packet.

Host B converts back from digital to analog as soon as it receives a whole packet.

How much time elapses from when the first bit starts to be created until the conversion back to analog begins? Give answer in milliseconds (ms) to two decimal places, normal rounding, without units (e.g. 1.5623 ms would be entered as "1.56" without the quotes)

part 2)

Suppose there are 2 routers in sequence between Host A and Host B, all of which use store-and-forward routing. What is the total end-to-end delay for a packet originating from Host A with destination Host B, under the following conditions.

Each of the link transmission rates are 6.2 Mbps

The total distance from Host A to Host B along its path of transmisison is 134.3 km

The speed of propagation through the transmission medium is is 2.7 x 108 m/s

The packet size is 4 KiB

Remember that you must also uplink from Host A to the first router. Give answer in milliseconds, rounded to 1 decimal place, without units (e.g. for 0.12345 seconds you would enter "123.5" without the quotes).

Explanation / Answer

As per this question,there are 2 routers in sequence between Host A and Host B and using store-and-forward routing.
So that time would consist of both propagation delay and transmission time

Propagation delay is nothing but the time taken for travelling.
Transmission delay is the amount of delay time from the beginning to end of transmission)
Now,
Propagation delay = distance travelled / speed of propagation
= 161200 / 2.7 *108 = 59703703.70 * 10-8 mili sec

Transmssion delay:
= packet size / bandwidth
= 4 / (9.1 * 1024) = 4.2925 * 10-1 mili sec

Let us assume routers have zero (0) processing time
total time = Transmssion delay by host A + Transmssion delay by router1 + Transmssion delay by router2 + propagation time
= 3 * ( 4.2925 * 10-1 ) + (59703703.70 * 10-8)
= 1.28775 + 0.5970370370 ms
= 1.884787 ms

part2:

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