A person is standing on a level floor. His head, upper torso, armsand hands toge

Question

A person is standing on a level floor. His head, upper torso, armsand hands together weigh 48 N and have a center of gravity that is1.28 m above the floor. His upper legs weigh 144 N and have acenter of gravity that is .760m above the floor. Finally, his lowerlegs and feet together weigh 87 N and have a center of gravity thatis .250m above the floor. Relative to the floor, find the locationof the center of gravity for his entire body.

The back of the book says the answer is 1.03 m. I don't knowhow it got that.

The back of the book says the answer is 1.03 m. I don't knowhow it got that.

Explanation / Answer

(m1r1+m2r2+m3r3)/(m1+m2+m3) =(m1r1+m2r2+m3r3)g/(m1+m2+m3)g =(w1r1+w2r2+w3r3)/(w1+w2+w3) here w1=48N,r1=1.28 m w2=144N,r2=0.76m w3=87N,r3=0.25m center of gravity is 0.69 m above ground

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.