Three forces acting on an object are given by F 1 = (1.75 i - 2.50 j ) N, F 2 =

Question

Three forces acting on an object are given by F1 = (1.75 i - 2.50 j ) N, F2 = ( 5.00 i + 3.35 j )N, and 3 = ( - 41.0 i ) N.The object experiences an acceleration of magnitude 3.75 m/s2. (a) What is the direction of theacceleration?
° (from the positive xaxis)

(b) What is the mass of the object?
kg

(c) If the object is initially at rest, what is its speed after20.0 s?
m/s

(d) What are the velocity components of the object after20.0 s?
( i +j ) m/s (a) What is the direction of theacceleration?
° (from the positive xaxis)

(b) What is the mass of the object?
kg

(c) If the object is initially at rest, what is its speed after20.0 s?
m/s

(d) What are the velocity components of the object after20.0 s?
( i +j ) m/s

Explanation / Answer

a)
the force acting on the object is                         Fnet= F1+F2+F3          on adding thex, y components                               = Fxi + Fyj the direction of force                             tan = Fy /Fx                                 = tan^-1  (Fy/Fx)
b)
the mass of the object                              m = | F | / a
c)
the speed of the object after time interval t                  v = at^2/2

d)
the velocity components are                   vx = ax / t and vy =ay / t

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