A physics student on a bungey jump drops a watermelon onto somepeople standing b

Question

A physics student on a bungey jump drops a watermelon onto somepeople standing below. if the student was travelling downward at14.05 ms-1 when she dropped the watermelon and it took 1.7s for thewatermelon to hit the people.

i) how high was the bungey when the student dumped thewatermelon?

ii)what speed did the watermelon have just before itsplattered?

iii) the watermelon had a mass of 1.2 kg. what was the totalchange in energy of the watermelon between the time it wasdropped and just before it hit the people? Explain youranswer.

Explanation / Answer

the velocity of water melon is 1.7*9.8+14.05=30.71m/sec the average velocity as the motion is uniform is30.71+14.05/2=22.38m/sec the distance traveled is 1.7*22.38=38.046m=height b)this is the first line c)this is 0 during this time as there is no non conservative force involved for the loss of energy

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.