I don\'t know how to work part c of this problem (I copied andpasted the solutio

Question

I don't know how to work part c of this problem (I copied andpasted the solution given on the site) radius r = 3220 km = 3.22 x 106 m
velocity v = 29,000 km/hr = 8 x 103 m/s

a) we know that v = r
                         = v/r
angular velocity =  ( 8 x 103 m/s )/ 3.22 x 106m
                            = 0.0025 rad/s

b) the radial acceleration ar =2r
                                      ar = (.0025)2(3.22 x106)
                                      ar = 20.15 m/s2

c) at = r
     at = 1/rdv    How do we get to here? What equation,method etc do we use to substitude for to get me tothis step?          = 1/r x0          =0 I don't know how to work part c of this problem (I copied andpasted the solution given on the site) radius r = 3220 km = 3.22 x 106 m
velocity v = 29,000 km/hr = 8 x 103 m/s

a) we know that v = r
                         = v/r
angular velocity =  ( 8 x 103 m/s )/ 3.22 x 106m
                            = 0.0025 rad/s

b) the radial acceleration ar =2r
                                      ar = (.0025)2(3.22 x106)
                                      ar = 20.15 m/s2

c) at = r
     at = 1/rdv    How do we get to here? What equation,method etc do we use to substitude for to get me tothis step?          = 1/r x0          =0

Explanation / Answer

I do not know the question, but I believe the answer of c iswrong. at is the acceleration m/s2 1/r (r is radius) 1/m dv (the change in velocity) m/s at = 1/r dv means m/s2=1/s ???? From my point of view, at simply is at=dv/dt Because v=constant, dv=0 Hence at=0

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