I don\'t know how to visualize or start this problem from myhomework. A skateboa
ID: 1663824 • Letter: I
Question
I don't know how to visualize or start this problem from myhomework. A skateboarder shoots off a ramp with a velocity of6.8 m/s, directed at an angle of59° above the horizontal. The end ofthe ramp is 1.1 m above the ground. Letthe x axis be parallel to the ground, the +ydirection be vertically upward, and take as the origin the point onthe ground directly below the top of the ramp. Please help THANK YOU! I don't know how to visualize or start this problem from myhomework. A skateboarder shoots off a ramp with a velocity of6.8 m/s, directed at an angle of59° above the horizontal. The end ofthe ramp is 1.1 m above the ground. Letthe x axis be parallel to the ground, the +ydirection be vertically upward, and take as the origin the point onthe ground directly below the top of the ramp. Please help THANK YOU!Explanation / Answer
I just got done with this problem. For the maximum height you have to use the equation y=Vfy^2-Voy^2/2(a) and you can cancel out Vf and Vo is 6.8cos59. Then from there find the time it took you to reach that height and I'm pretty sure I just used the simple equation x=Vox*t. Try that! if it doesn't work, sorry :(
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