A positive point charge Q 1 = 1.7 x10 -5 C is fixed at the origin of coordinates

Question

A positive point charge Q1 = 1.7 x10-5 C is fixed at the origin of coordinates, and anegative charge Q2 = -8.3 x 10-6 C isfixed to the x axis at x = +2.0 m. Find the location of theplace(s) along the x axis where the electric field due to these twocharges is zero.
x = 1 m
x = 2 m A positive point charge Q1 = 1.7 x10-5 C is fixed at the origin of coordinates, and anegative charge Q2 = -8.3 x 10-6 C isfixed to the x axis at x = +2.0 m. Find the location of theplace(s) along the x axis where the electric field due to these twocharges is zero.
x = 1 m
x = 2 m

Explanation / Answer

Charges Q1 = 1.7 * 10 ^ -5 C

             Q2 = 8.3 * 10 ^ -6 C

Separation x = 2 m

If the electric field at the required point due to charge Q1 isequal in magnitude but opposite in direction to the electric fieldat that point due to Q2 then net electric field at that point iszero.

i.e., electric field due to Q1= electric field due toQ2

           KQ1/ x ^ 2 = KQ2 / ( r-x ) ^ 2

    [(r-x) / x ] ^ 2 = Q 2 / Q1

                          = 4.882

              (r-x)/ x = 2.209

                     r-x= 2.209 x

                         r = 3.209 x

                         x = r / 3.209

                            = 0.623 m

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