A positive point charge Q 1=3.6×105C is fixed at the origin of coordinates, and

Question

A positive point charge Q1=3.6×105C is fixed at the origin of coordinates, and a negative point charge Q2=4.1×106C is fixed to the x axis at x=+1.5m.

Part A

Find the location of the place(s) along the x axis where the electric field due to these two charges is zero.

A positive point charge Q1=3.6×105C is fixed at the origin of coordinates, and a negative point charge Q2=4.1×106C is fixed to the x axis at x=+1.5m.

Part A

Find the location of the place(s) along the x axis where the electric field due to these two charges is zero.

Explanation / Answer

as the two charges are opposite

the point of zero electric field lies out side the line joinig the two charges

Q > Q2

point of zero electric field lies nearer to Q2

let at x > x1 from the origin the

E1 = k*Q1/x^2

E2 = k*Q2/(x-x1)^2

E1 = E2

k*Q1/x^2 = k*Q2/(x-x1)^2

Q1/x^2 = Q2/(x-x1)^2

(3.6*10^-5)/x^2 = (4.1*10^-6)/(x-1.5)^2

x = 2.26 m

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