Two converging lenses, each of focal length 16.5 cm, are placed 39.8 cm apart, a
ID: 1673374 • Letter: T
Question
Two converging lenses, each of focal length 16.5 cm, are placed 39.8 cm apart, and an object is placed 30.0 cm infront of the first lens. Where is the final image formed?(hint:final image will be formed in front of the secondlense) What is the magnification of the system?Two converging lenses, each of focal length 16.5 cm, are placed 39.8 cm apart, and an object is placed 30.0 cm infront of the first lens. Where is the final image formed?(hint:final image will be formed in front of the secondlense) What is the magnification of the system?
Explanation / Answer
from the thin lens equation we get the imageposition of the first lens as
q1 = p1 f1 /(p1 - f1)
= (30.0 cm) (16.5 cm) /(13.5 cm)
= ...... cm
the magnification by this lens will be
M1 = - q1 / p1
= - ........
the real image formed by the first lens serves as anobject for the second lens so we get
p2 = 39.8 cm - q1
= ......... cm
so from the thin lens equation we get
q2 = p2 f2 /(p2 - f2)
= ......... cm
the magnification by this lens will be
M2 = - q2 / p2
= ........
the final image is virtual and
the overall magnification is given by
M = M1 M2
= ........
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