A block weighing 9.07 N rests on a33° inclined plane. (a) Find the normal force

Question

A block weighing 9.07 N rests on a33° inclined plane. (a) Find the normal force exerted by the planeon the block.
1 N out of the plane

(b) Find the frictional force exerted by the plane on theblock.
2 N up the slope

(c) Find the magnitude of the total force exerted by the plane onthe block
3 N

(d) Find the normal force and the frictional force exerted by theblock on the plane. normal force 4 N into the plane frictional friction 5 N down the slope (a) Find the normal force exerted by the planeon the block.
1 N out of the plane

(b) Find the frictional force exerted by the plane on theblock.
2 N up the slope

(c) Find the magnitude of the total force exerted by the plane onthe block
3 N

(d) Find the normal force and the frictional force exerted by theblock on the plane. normal force 4 N into the plane frictional friction 5 N down the slope normal force 4 N into the plane frictional friction 5 N down the slope

Explanation / Answer

1. N = mgcos = 9.07cos33 = 7.61 N 2. f = mgsin = 9.07sin33 = 4.94 N 3. |F| = mg =9.07 N 4. |N'|=|N|=7.61 N 5. |f'|=|f|=4.94 N

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