1. A spring with a spring constant k = 1600 N/mis at rest on the bottom of an in
ID: 1672532 • Letter: 1
Question
1. A spring with a spring constant k = 1600 N/mis at rest on the bottom of an inclined plane. A 7.0-kg blockslides down the plane and makes contact with the spring at point Aas shown. After contact, the spring is compressed to point B, 0.20m from point A, where the speed of the block is zero m/s. What wasthe speed of the block just before contact with the spring?2.A cylinder with a diameterof 0.240 m is placed between the plates of a hydraulic press asillustrated in the drawing. A 4.45 × 105-N forceis applied to the cylinder. What is the pressure on the end of thecylinder due to the applied force?
2.A cylinder with a diameterof 0.240 m is placed between the plates of a hydraulic press asillustrated in the drawing. A 4.45 × 105-N forceis applied to the cylinder. What is the pressure on the end of thecylinder due to the applied force?
Explanation / Answer
We can use kinetic energy and potential energy to solve forspeed. Potential Energy put into spring = Kinetic Energy of block beforebefore making contact PE of Spring = 1/2 kx2 PE = (1/2) (1600 N/m) (0.20m)2 PE = 32.0 N-m = 32.0 J PE = KE KE of block = 1/2 mv2 32.0 J = 1/2 (7.0 kg) v2 v = 3.024 m/s is the velocity of the block before hitting thespring 2. Pressure = Force/Area Area at bottom of cylinder is the area of a circle r2 2r = diameter 0.240 m = 2r r = 0.120 m A = (0.120m)2 A = 4.5239 x 10-2 m2 P = F/A P = (4.45 ×105-N)/4.5239 x 10-2 m2 P = 9.8367 x 106 N/m2
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