1. A solution is made by dissolving 1.00 g of the ligan bipyridine ( C10 H8 N2)

Question

1. A solution is made by dissolving 1.00 g of the ligan bipyridine ( C10 H8 N2) in enough water to make 1.00 L of solution. Determine the concentration of bipyridine in the following solutions:

A) take 10.0 mL of the original solution and add enough water to make 100. mL of solution.

B) take 0.40 mL of the original solution and mix in a cuvette with 0.50 ml of hydroxylamine and 1.40 mL of iron solution.

C) mix 1.00 mL of the solution from part a with 1.20 mL of hydroxylamine solution and .40 mL of iron solution.

PLEASE SHOW ALL WORK

Explanation / Answer

M1V1= M2V2 is formula we use

solute moles = 1/156 = 0.0064

initial M = 0.0064/1 = 0.0064 M

A) 0.0064 x 10 = M x 100

M = 0.00064   = 6.4 x10^ -4 M

B) moles of bipyridine = 0.0004 x 0.0064 = 2.56 x 10^ -6
Vol = ( 0.0004+ 0.0005 + 0.0014) = 0.0023

M = ( 2.56 x10^ -6)/0.0023 = 0.0011 M = 1.1 x10^ -3 M

C) moles of solute = 0.00064 x 0.001 = 6.4 x10^ -7 ,

Vol = 0.001+0.0012+0.0004 = 0.0026 liters

M = ( 6.4 x10^ -7)/( 0.0026)   = 0.000246 M = 2.46 x10^ -4 M

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