1. A solution of ammonia is 2.0% ionized at 25.0 degrees celsius.What was the or
ID: 684324 • Letter: 1
Question
1. A solution of ammonia is 2.0% ionized at 25.0 degrees celsius.What was the original concentration ( in M) of the ammoniasolution? The Kb at 25.0 degrees celsius for ammonia is4.8 x 10-5.The answer to this question is 4.41 x 10-2. Pleaseexplain the calculation steps (SIMPLY) of how to get to thisanswer.
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2. Selenous Acid, H2SeO3, is a weak diproticacid. A 0.10 M solution of sodium hydrogen selenate willbe________. Ka = 2.3 X 103, Ka2 =5.3 x 109. Choose One Answer butExplain why you chose it.
A. Acidic
B. Neutral
C. Basic
D. Insufficient Information to determine.
Explanation / Answer
We Know that : NH3 +H2O ------> NH4+ +OH- I: M 0 0 C: -x +x +x E : M-x +x +x Kb = 4.8 x 10-5. 1.8 x 10-5. = [ x ]2 / [M-x ] ignoring the value M-x we have get the value of x as 0.00692 x / M x 100 = 2.0 0.00692 / M x 100 = 2.0 intial concentration of the base taken = 0.346 M b. As theselenous acid is a weak acid the given concentration of sodiumselenate it behaves as strongly basic in natureit ionizes to give the basic solution in the presence of baseNaOH.Related Questions
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