A real ammerter has non-zero resistance, and so acts like aresistor in a circuit

Question

A real ammerter has non-zero resistance, and so acts like aresistor in a circuit. One ammerter has resistance 0.5. Whenit is placed across a battery (with emf and internalresistance r), the terminal voltage of the battery is 5.0V. Adifferent ammerter has resistance 0.25. When it is placedacross the same battery, the terminal voltage is 2.94V. Determinethe emf and the internal resistance of the battery. A real ammerter has non-zero resistance, and so acts like aresistor in a circuit. One ammerter has resistance 0.5. Whenit is placed across a battery (with emf and internalresistance r), the terminal voltage of the battery is 5.0V. Adifferent ammerter has resistance 0.25. When it is placedacross the same battery, the terminal voltage is 2.94V. Determinethe emf and the internal resistance of the battery.

Explanation / Answer

we know that terminal voltage =ER/E+r where E=emf R=external resistance r=internal resistance so as per the data E*0.5/0.5+r=5----1 and E*0.25/0.25+r=5----2solving these 2 eqs we have internal resistance=r=1.1704ohm also emf=16.704V

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