A particle the has an 8.2-C charge moves with a velocity ofmagnitude 5.0 x 10 5

Question

A particle the has an 8.2-C charge moves with a velocity ofmagnitude 5.0 x 105 m/s along the + x axis. Itexperienced no magnetic force, although there is a magnetic fieldpresent. The maximum possible magnetic force that the charge couldexperience has a magnitude of 0.48 N. Find the magnitude anddirection of the magnetic field. Note there are two possibleanswers for the direction of the field

Explanation / Answer

Given that F = 0.48 N q = 8.2 C v = 5.0 x 105 m/s We know that             F = B q v ==>   B = F / q v              = 0.48 / 8.2 x 10-6 * 5 x 105              = 0.1170 T along the negative y - direction.

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