This is another gordon rule question Q#1 A hand exerts a constant horizontal for
ID: 1670818 • Letter: T
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This is another gordon rule question Q#1 A hand exerts a constant horizontal force on a block that isfree to slide on a frictionless surface. The block start from restat point A, and by the time it has travelled a distance to point B,it is travelling with a speed Vb. when the block has travelledanother distance to point C, will its speed be greater than, lessthan, or equel to 2vB? Explain in great detail your reasoning.Hint--- consider using the Work-Energy principle. This is another gordon rule question Q#1 A hand exerts a constant horizontal force on a block that isfree to slide on a frictionless surface. The block start from restat point A, and by the time it has travelled a distance to point B,it is travelling with a speed Vb. when the block has travelledanother distance to point C, will its speed be greater than, lessthan, or equel to 2vB? Explain in great detail your reasoning.Hint--- consider using the Work-Energy principle.Explanation / Answer
I suppose that distance AB and BC aresame. According to work energyprinciple, workdone = change in k.e. ofobject Work done from A toB WAB = F* d where d = distancebetween A and B then K = KB - KA F *d = (1/2) * m *vb2 - (1/2)* m * 02 F *d = (1/2) * m *vb2 -------------(1) F *d = (1/2) * m *vb2 -------------(1) vb = (2* F * d /m) -------------(2) Between B and C WBC = F* d and F* d = (1/2) * m *vc2 - (1/2)* m * vb2 = (1/2)* m * vc2 - F *d (from equation (1)) => 2* F *d = (1/2)* m * vc2 vc = (4* F * d / m) ----------(3) Dividing equation (3) by equation (1) vc /vb = (4 * F * d/ m) / (2 * F * d / m) = 2 vc = vb* 2 hence the speed of object at C is less thantwice the speed of object at B. vc < 2* vb hence the speed of object at C is less thantwice the speed of object at B. vc < 2* vbRelated Questions
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