You have 12 m of 0.9 mm diameter copper wire and abattery capable of passing 25A

Question

You have 12 m of 0.9 mm diameter copper wire and abattery capable of passing 25A through the wire. (a) What magnetic field strength could you obtain inside a 2.0 cmdiameter solenoid wound with the wire as closely spaced aspossible?
________T

(b) What magnetic field strength could you obtain at the center ofa single circular loop made from the wire?
_________T

Hmmm! (a) What magnetic field strength could you obtain inside a 2.0 cmdiameter solenoid wound with the wire as closely spaced aspossible?
________T

(b) What magnetic field strength could you obtain at the center ofa single circular loop made from the wire?
_________T

Hmmm!

Explanation / Answer

The number s of turns in the soleniod is         N = 12m / 2 r here r = 0.01m       N = 12m / 2 (0.01)           = 191turns Length of the soleniod is L = (0.9x10^-3)(191)                                          = 0.1718m The magnetic field strength is           B =o N I / L            = ( 4x10^-7) (191)(25) / 0.1718            = 0.0349T            = 0.035T Magnetic field at the center of a single coil is         B =o I / 2 r Here 2 r = 12m           =(4x10^-7)(25) / 12           =2.62x10^-6 T

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