A loaded elevator has a total mass of 2200 kg. Thecables (attached to the top) c
ID: 1669023 • Letter: A
Question
A loaded elevator has a total mass of 2200 kg. Thecables (attached to the top) can withstand a maximum tension of28,000 N.A) What is the maximum upward acceleration thiselevator can withstand? B) Repeat (A) if the elevator alsoexperiences a friction force of 5,000 N on its way up.
C) The cable snaps. Assuming the samefrictional force in (B), find the new acceleration. A loaded elevator has a total mass of 2200 kg. Thecables (attached to the top) can withstand a maximum tension of28,000 N.
A) What is the maximum upward acceleration thiselevator can withstand? B) Repeat (A) if the elevator alsoexperiences a friction force of 5,000 N on its way up.
C) The cable snaps. Assuming the samefrictional force in (B), find the new acceleration.
Explanation / Answer
A) When elevator moves in upward direction we have T - Mg = Ma ==> a = [ T - Mg ] / M = [ 28000 - 2200 * 9.8] / 2200 = 2.927 m/s2 B) When elevator experiences a frictional force then T - f - Mg = Ma ==> a = [ T -f - Mg ] / M = [ 28000 - 5000 - 2200*9.8] / 2200 = 1440 / 2200 = 0.654 m/s2 C) When cable snaps then tension in the cable = 0, thenthe elevator moves in the downward direction, then Mg - f = Ma ==> a = [ Mg - f ] / M = [ 2200 *9.8 - 5000 ] / 2200 = 7.527 m/s2
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