A number 14 copperwire has a diameter of 1.628 mm. Calculate the resistance of a
ID: 1667881 • Letter: A
Question
A number 14 copperwire has a diameter of 1.628 mm. Calculate the resistance of a 31.0m long piece of such wire.(Use 1.72×10-8 ?m for the resistivity ofcopper.)
For safety, theNational Electrical Code limits the allowable amount of currentwhich such a wire may carry. When used in indoor wiring, the limitis 15.0 A for rubber insulated wire of that size. How much powerwould be dissipated in the wire of the above problem when carryingthe maximum allowable current?
What would be thevoltage between the ends of the wire in the aboveproblem?
What is the currentdensity in the wire when it is carrying the maximum allowablecurrent? (Current density is the current in the wire divided by thecross sectional area of the wire.)
What is the driftvelocity of the electrons when the wire is carrying the maximumallowable current?
(The density of electrons in copper is 8.47×1028m-3.)
Anumber 14 copper wire has a diameter of 1.628 mm. Calculate theresistance of a 31.0 m long piece of such wire.
(Use 1.72×10-8 ?m for the resistivity ofcopper.)
For safety, theNational Electrical Code limits the allowable amount of currentwhich such a wire may carry. When used in indoor wiring, the limitis 15.0 A for rubber insulated wire of that size. How much powerwould be dissipated in the wire of the above problem when carryingthe maximum allowable current?
What would bethe voltage between the ends of the wire in the aboveproblem?
What is thecurrent density in the wire when it is carrying the maximumallowable current? (Current density is the current in the wiredivided by the cross sectional area of the wire.)
What is thedrift velocity of the electrons when the wire is carrying themaximum allowable current?
(The density of electrons in copper is 8.47×1028m-3.)
Anumber 14 copper wire has a diameter of 1.628 mm. Calculate theresistance of a 31.0 m long piece of such wire.
(Use 1.72×10-8 ?m for the resistivity ofcopper.)
For safety, theNational Electrical Code limits the allowable amount of currentwhich such a wire may carry. When used in indoor wiring, the limitis 15.0 A for rubber insulated wire of that size. How much powerwould be dissipated in the wire of the above problem when carryingthe maximum allowable current?
What would bethe voltage between the ends of the wire in the aboveproblem?
What is thecurrent density in the wire when it is carrying the maximumallowable current? (Current density is the current in the wiredivided by the cross sectional area of the wire.)
What is thedrift velocity of the electrons when the wire is carrying themaximum allowable current?
(The density of electrons in copper is 8.47×1028m-3.)
Explanation / Answer
For the second part: "For safety...."
Power = I^2R
R is what you found in the first part, I is what is given
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