8 ohm resistor is mounted in parallel with a resistor R = 5ohm. and this combina

ID: 1667277 • Letter: 8

Question

8 ohm resistor is mounted in parallel with a resistor R = 5ohm. and this combination is connected in series with and 10 ohm resistor and a 12 v battery. what is my current thorughR resistor? and for this same question, what is the power dissipated inthe R resistor?? Thank you so much. 8 ohm resistor is mounted in parallel with a resistor R = 5ohm. and this combination is connected in series with and 10 ohm resistor and a 12 v battery. what is my current thorughR resistor? and for this same question, what is the power dissipated inthe R resistor?? Thank you so much.

Explanation / Answer

Resistor R1 = 8 , Resistor R2 =5 Resistor R3 = 10 R1 &R2 are in parallelis 1 / Rp = 1 / R1 +1/R2 =1 / 8 + 1/ 5 1/ Rp = 0.325 Rp = 3.07 This combination is connectedto R3 in series is R = Rp + R3 = 3.07 +10 = 13.07 Accordingto Ohm's law I =V /R = 12 V / 13.07 = 0.91 A Power dissipated in resistor is P =I2 R = ( 0.91 A )2 * 13.07 = 10.92 W = 3.07 +10 = 13.07 Accordingto Ohm's law I =V /R = 12 V / 13.07 = 0.91 A Power dissipated in resistor is P =I2 R = ( 0.91 A )2 * 13.07 = 10.92 W

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8 ohm resistor is mounted in parallel with a resistor R = 5ohm. and this combina

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