I got my own answers but wanted to confirm themplease! Will rate lifesaver if co
ID: 1665780 • Letter: I
Question
I got my own answers but wanted to confirm themplease! Will rate lifesaver if correct! =)1. A uniform conducting rod of length 24 cm hasa potential difference across its ends equal to 52 mV(millivolts).
What is the magnitude of the electric field inside the conductor inunits of N/C? 2. A cylindrical rod has a length of 27 cm and adiameter of 1.6 mm. What is the cross-sectional area inm2? 3. Several wires of varying thickness are allmade of the same material and all have the same length. If thewires are arranged in order of increasing thickness, what can besaid about the ordering of their resistance?
1. The ordering of the resistances cannot be determined because the length is not given.
2. The wires will be arrangedin order of increasing resistance.
3. The wires will be arrangedin order of decreasing resistance.
4. The ordering of theresistances can not be determined because the resistivity is notgiven.
I got my own answers but wanted to confirm themplease! Will rate lifesaver if correct! =)
1. A uniform conducting rod of length 24 cm hasa potential difference across its ends equal to 52 mV(millivolts).
What is the magnitude of the electric field inside the conductor inunits of N/C? 2. A cylindrical rod has a length of 27 cm and adiameter of 1.6 mm. What is the cross-sectional area inm2? 3. Several wires of varying thickness are allmade of the same material and all have the same length. If thewires are arranged in order of increasing thickness, what can besaid about the ordering of their resistance?
1. The ordering of the resistances cannot be determined because the length is not given.
2. The wires will be arrangedin order of increasing resistance.
3. The wires will be arrangedin order of decreasing resistance.
4. The ordering of theresistances can not be determined because the resistivity is notgiven.
Explanation / Answer
1. Electricfield E = Potentialdifference / distance = 52mV / 24 cm = 52* 10-3 / 24 * 10-2 = 0.2167 V/m = 0.2167N/C (as V/m and N/C are same) = 0.2167 V/m = 0.2167N/C (as V/m and N/C are same) 2. Area of crosssection A = r2 = 3.14* ( 1.6 * 10-3)2 = 8.04* 10-6 m2 = 8.04* 10-6 m2 3. 3. The wires will bearranged in order of decreasing resistance R = * L / A more thickness means more area of crosssection (A) i.e. less resistance.Related Questions
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