An electron passes through a potential difference of 300 V as it isdirected towa

Question

An electron passes through a potential difference of 300 V as it isdirected toward the screen of a CRt. assuming that the electron wasat rest when it started, how fast is the electron going when ithits the CRt screen?
also Four 2.0x10-6C charges are arranged at the courners of asquare of side .20m. what is the magnitude and direction of theelectric field on the charge in the upper right corner due to theother three charges?
also Four 2.0x10-6C charges are arranged at the courners of asquare of side .20m. what is the magnitude and direction of theelectric field on the charge in the upper right corner due to theother three charges?

Explanation / Answer

Potential difference V = 300 V Charge q = 1.6 * 10 ^ -19 C mass m = 9.11 * 10 ^ -31kg Initial speed u = 0 Let the final speed be v then from work done = Change in kinetic energy                       Vq = ( 1/ 2) mv ^ 2                          v = [ 2Vq / m] plug the values we get v = 10.265* 10 ^ 6 m / s

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