An electron moves with a speed of 2.010 7 m/s in the directions shown in the fig

Question

An electron moves with a speed of 2.0107m/s in the directions shown in the figure. A 0.40T magnetic field points in the positive x-direction.(Figure 1)

What is the magnitude of the magnetic force in figure (a)?

What is the direction of the magnetic force in figure (a)?

What is the magnitude of the magnetic force in figure (b)?

What is the direction of the magnetic force in figure (b)?

An electron moves with a speed of 2.0107m/s in the directions shown in the figure. A 0.40T magnetic field points in the positive x-direction.(Figure 1) What is the magnitude of the magnetic force in figure (a)? What is the direction of the magnetic force in figure (a)? What is the magnitude of the magnetic force in figure (b)? What is the direction of the magnetic force in figure (b)?

Explanation / Answer

magnitude of the magnetic force in figure (a) = B*v*q*sin90

=12.8*10-13 N

direction of the magnetic force in figure (a) is positive z direction

magnitude of the magnetic force in figure (b) =B*v*q*sin90

=12.8*10-13 N

direction of the magnetic force in figure (b) is j^ +k^(that is in direction of cross product of v and B)

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