A small piece of dust ofmass m = 4.7 µg travels through an electric aircleaner i

Question

A small piece of dust ofmass m = 4.7 µg travels through an electric aircleaner in which the electric field is 527 N/C. The electric force on the dustparticle is equal to the weight of the particle. (a) What is the charge on the dust particle?
C

(b) If this charge is provided by an excess of electrons, how manyelectrons does that correspond to?
electrons (a) What is the charge on the dust particle?
C

(b) If this charge is provided by an excess of electrons, how manyelectrons does that correspond to?
electrons

Explanation / Answer

The gravity force equal to the electric force Fg=Fe Fg=mg Fe=Eq so mg=Eq q=mg/E=8,74e-8(C) the charge of a electron is 1,6e-19 (C) so the number of the electron N=8,74e-8/1,6e-19=5,46e11

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