In a 4-hr period a hiker walked 5.0 km during the first hourand 4.4 km during th

Question

In a 4-hr period a hiker walked 5.0 km during the first hourand 4.4 km during the second hour. After resting for an hour, thehiker walked 4.6 km during the 4th hour. What was the average speedduring a) the first two hours b) the first three hours c) the entire 4 hour period I've worked it out but I'm not sure if I done itcorrectly In a 4-hr period a hiker walked 5.0 km during the first hourand 4.4 km during the second hour. After resting for an hour, thehiker walked 4.6 km during the 4th hour. What was the average speedduring a) the first two hours b) the first three hours c) the entire 4 hour period I've worked it out but I'm not sure if I done itcorrectly

Explanation / Answer

a) the first two hours = (hour1speed+hour2speed)/2 so (5+4.4)/2=4.7 km/hr b) the first three hours= (hour1speed+hour2speed+hour3speed)/3 (5+4.4+0)/3=3.1 km/hr c) the entire 4 hour period = (hour1speed+hour2speed+hour3speed+hour4speed)/4 (5+4.4+0+4.6)/4=3.5 km/hr

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