A scout walks 9 km due east from camp,then turns left and walks 2.7 km along the

Question

A scout walks 9 km due east from camp,then turns left and walks 2.7 km along thearc of a circle centered at the campsite, and finally walks5.4 km directly toward the camp. (a) How far is the scout from camp at the endof his walk?
1 km

(b) In what direction is the scout's position relative to thecampsite?
2° (clockwise from north)

(c) What is the ratio of the final magnitude of the displacement tothe total distance walked?
(a) How far is the scout from camp at the endof his walk?
1 km

(b) In what direction is the scout's position relative to thecampsite?
2° (clockwise from north)

(c) What is the ratio of the final magnitude of the displacement tothe total distance walked?

Explanation / Answer

A. assuming he starts at the camp: he went 9 km away, and 5.4 km directly towards. so d = 9-5.4 = 3.6 km For part b, it says he walks 2.7 km along the arc of thecircle. so, 2.7 =R          where R is the radius of the circle (which is 9 km) 2.7/9 =          Thisis in radians. To convert to degrees, 2 rad = 360degrees==> 1 rad = 360/2 degrees For part C, the total distance walked is D = 9+5.4 +2.7 the final magnitude of displacement was found in part a which was3.6 km. 3.6/D = the ratio of displacement to total distance walked.

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