A rigid, insulating fiber runs along a portion of the y -axis; the fiber isnot f

Question

A rigid, insulating fiber runs along a portion of they-axis; the fiber isnot free to move. Gravity actsdownward (g = 9.81 m/s2).A chargeQa = -3 µC is fixed to the fiber at theorigin. A bead with a hole drilled through its center is slippedover the fiber andis free to move along the fiber without friction.The mass of the bead is m = 160 gand its charge isQb. At equilibrium, the bead floats adistanceyb = 11 cm above the origin a.) Calculate the charge on the bead. b) If the mass of the bead were tripled (m' =3m), how far above the origin wouldit now float atequilibrium?
The bead (with original mass m) is removed andits charge altered to Qc. Whenplaced on thefiber from below, it floats at equilibrium pointyc = -15 cmbelow the origin. c.) What is this new charge? Please show work.

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