A 5g bullet is fired with a velocity of 100m/s toward a 10kgstationary block on

Question

A 5g bullet is fired with a velocity of 100m/s toward a 10kgstationary block on a frictionless surface. a) What is the change in momentum of the bullet if it isemedded in the block. P1=M1V1 P1= .05kg m/s P2= 5 kg m/s So the difference would be 4.95kg m/s b) what is the change in momentum of the bullet if itricochets in the opposite direction with a speed of 99 m/s? p1-p2= .445kg m/s c) In which case does the block end up with graterspeed? The block would end up with more speed in the first situationdue to all the momentum contained in the block itself. A 5g bullet is fired with a velocity of 100m/s toward a 10kgstationary block on a frictionless surface. a) What is the change in momentum of the bullet if it isemedded in the block. P1=M1V1 P1= .05kg m/s P2= 5 kg m/s So the difference would be 4.95kg m/s b) what is the change in momentum of the bullet if itricochets in the opposite direction with a speed of 99 m/s? p1-p2= .445kg m/s c) In which case does the block end up with graterspeed? The block would end up with more speed in the first situationdue to all the momentum contained in the block itself.

Explanation / Answer

m = 5 g, M = 10 kg, v = 100 m/s a) mv = (M + m)V, V = mv/(M + m) = 0.049975 m/s a) change in momentum of the bullet = m(v - V) = 0.4997 kgm/s b) v' = -99 m/s change in momentum of the bullet = m(v - v') = 0.995 kgm/s c) the second situation, (speed v' >> V)

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