Three resistors, R1 = 26 , R2 = 80 , and R3=R, are connected in parallel with a

Question

Three resistors, R1 = 26 , R2 = 80 , and R3=R, are connected in parallel with a 12 V battery.
A.) The total current flowing through the battery is 0.88 A . Find the value of resistance R.
B.) Find the current through each resistor.
C.) If the total current in the battery had been greater than 0.88 A , would your answer to part A have been larger or smaller? Explain.
Three resistors, R1 = 26 , R2 = 80 , and R3=R, are connected in parallel with a 12 V battery.
A.) The total current flowing through the battery is 0.88 A . Find the value of resistance R.
B.) Find the current through each resistor.
C.) If the total current in the battery had been greater than 0.88 A , would your answer to part A have been larger or smaller? Explain.

A.) The total current flowing through the battery is 0.88 A . Find the value of resistance R.
B.) Find the current through each resistor.
C.) If the total current in the battery had been greater than 0.88 A , would your answer to part A have been larger or smaller? Explain.

Explanation / Answer

here,

R1 = 26 ohm , R2 = 80 ohm

R1 = R

a)

the equivalent resistance , Req = 12 /0.88 = 13.63 ohm

as they are in parallel

1/Req = 1/R1 + 1/R2 + 1/R3

1/13.63 = 1/26 + 1/80 + 1/R

solving for R

R = 44.6 ohm

b)

the current through R1 , I1 = V/R1 = 0.46 A

the current through R2 , I2 = V/R2 = 0.15 A

the current through R3 , I3 = V/R3 = 0.27 A

c)

when the current is more than 0.88 A

as the resistances are in parallel

Req decreases

the value of R decreases

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.