Three resistors are joined together across a 6 Volts battery (see the figure). T

Question

Three resistors are joined together across a 6 Volts battery (see the figure). The voltage drop across resistor R1 is 1.654 Volts, the current i2 through resistor R2 is 0.057 A, and the power dissipated in resistor R3 is 0.190 W. What is the value of each resistor? R1? R2? R3? What is the current through each resistor? I1? I3? What is the power dissipated in each resistor? P1? P2? Find the total resistance of the network. Find the current drawn from the battery. And finally, find the total power used by the circuit. Thanks!

Explanation / Answer

voltage accross R3 = 6 - 1.654 =4.346,,,,,,power dissipated in resistor R3 =0.190 W = Vi3,,,,,i3 = 0.0437 A,,,,,,R3 =99.45 ohm,,,,,,,,i2= 0.057 A,,,,,,,,,i1=i2+i3=0.1007 A,,,,,,,,R1=1.654/i1= 16.4 ohm ,,,,,,,,,,,R2 =4.346/i2 =76.3 ohm,,,,,,,P1=V1*i1=0.17 W,,,,,,,,,,,P2=V2*i2=0.247 Watt,,,,,,,,equivalent resistance =59.57 ohm

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