A spherical capacitor is composed of an inner sphere which has a radius R 1 and
ID: 1658922 • Letter: A
Question
A spherical capacitor is composed of an inner sphere which has a radius R1 and a charge +Q and an outer concentric spherical thin shell which has a radius R2 and a charge Q.
(a) Find the electric field and the energy density as a function of r, where r is the distance from the center of the sphere, for 0 r . (Use the following as necessary: k, Q, r, and .)
0
0
kQr2
0
0
(b) Calculate the energy associated with the electrostatic field in a spherical shell between the conductors that has a radius r, a thickness dr, and a volume 4r2dr. (Use the following as necessary: k, Q, r, and dr.)
dU =.5kQ2r2dr
(c) Integrate your expression from Part (b) to find the total energy and compare your result with the result obtained using U = ½QV. (Use the following as necessary: Q, k, , R1, and R2.)
Er<R1 =0
ur<R1 =0
ER1<r<R2 =kQr2
uR1<r<R2 = Er>R2 =0
ur>R2 =0
Explanation / Answer
given, radius of inner sphere = R1, charge = Q
Outer spherical thin shell radius = R2, charge = -Q
a. for r < R1
E = 0 ( electric field inside conductor is 0)
so as E = 0, so energy density u = 0
for R1 < r < R2
form gauss law
E*4*pi*r^2 = Q/epsilon ( where epsilon is permittvity of free space)
so E = Q/4*pi*r^2*epsilon
now k = 1/4*pi*epsilon = coloumbs constant
E = kQ/r^2
u = 0.5*epsilon*E^2
u = 0.5*epsilon*k^2Q^2/r^4
u = 0.5*epsilon*Q^2/16*pi^2*epsilon^2*r^4
u = Q^2/32*pi^2*epsilon*r^4
for r > R2
From gauss law
E *4*pi*r^2 = qen/epsilon = (Q - Q)/epsilon = 0
so E = 0
and u = 0
b. energy associated with electric field fopr radius r and thickness dr ( R1 < r < R2)
dE = u(r)*4*pi*r^2*dr
dE = Q^2*4*pi*r^2*dr/32*pi^2*epsilon*r^4
dE = Q^2*dr/8*pi*epsilon*r^2
c. total energy = integrate dE form R1 to R2
E = Q^2[1/R2 - 1/R1]/8*pi*epsilon
now capacitance of spherical capacitor is given by
C = 4*pi*epsilon(R1R2/(R2 - R1))
for Voltage applied V, Charge Q
Energy stored in capacitor = 0.5CV^2 = 0.5Q^2/C
E = 0.5*Q^2(1/R2 - 1/R1)/4*pi*epsilon
E = Q^2(1/R2 - 1/R1)/8*pi*epsilon
hence the two energies match
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