00 T-Mobile LTE 11:43 PM tps://use1 1 fl.theexpertta.con ® HW 5 Begin Date:9/11/

Question

00 T-Mobile LTE 11:43 PM tps://use1 1 fl.theexpertta.con ® HW 5 Begin Date:9/11/2017 11:00:00 AM-Due Date: 9/25/2017 11:00:00 AM End Date: 9/25/2017 11:00:00 AM 11%) Preblem * Consider a eyliedial cable with a hangmg weights ended from it 33% Part (a) when the mass is removed, the length of the cable is found to be lo- 4.73 m. After the mass is added, the length is remeasured and found to be l1-5.37 m Determine Young's Modulus Yin Nm2 for the steel cable if the weight has a mass m = 95 kg and the cable has a radiusr- 0.045 m 33% Part (b) If we were to double the radius of the wire and re-suspend the weight, which of the following would be correct 33% Part (c) If this cable is pulled down a distance d in m from its equilibrium position it acts like a spring when released. Write an expression determining the spring constant k of this material using the cable-specific variables Y,l, lo, and r provided in part A Al content © 2017 Expert TL LLC

Explanation / Answer

mass of the load, m=95 kg

radius of the cable, r=0.045 m

extension in length of cable, dl=l1-l0

dl=5.37-4.73

dl=0.64 m

radius of the cable, r=0.045 m

a)

Young's modulus, Y=stress/strain

stress=F/A

=m*g/(pi*r^2)

=95*9.8/(pi*0.045^2)

=1.46*10^5 N/m^2

and

strain = dl/lo

=0.64/4.73

=0.135

now,

Y=stress/strain

=1.46*10^5/(0.135)

=1.08*10^6 N/m^2

C)

Y=stress/strain

Y=(k*d/A)/((l1-l0)/lo)

Y*(l1-lo)/lo=k*d/A

===> K=Y*(l1-lo)/lo*(A/d)

===> K=Y*(l1-lo)/lo*(pi*r^2)/d

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.