0/3 points ! Previous Answers walkers 12P074 My Notes Ask Your An equilateral tr

Question

0/3 points ! Previous Answers walkers 12P074 My Notes Ask Your An equilateral triangle 33.0 m on a side has a mi -5.00-kg mass at one corner, a m2-70.00-kg mass at another corner, and a m 75.00 kg mass at the third corner Find the magnitude and direction of the net force acting on the 5.00-kg mass. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, N Your response differs from the correct answer by more than 10%. Double check your calculations. counterclockwise from the positive rats ms m, m2 Submit Answer Save Progress

Explanation / Answer

a) F = G m1 m2 / r2

F1 = 6.67 * 10-11 * 5 * 75 / 332 = 2.29 * 10-11

F2 = 6.67 * 10-11 * 5 * 70 / 332 = 2.14 * 10-11

Fx = F1 sin 30 - F2 sin 30 = (2.29 * 10-11 * sin 30) - (2.14 * 10-11 * sin 30) = 7.5 * 10-13

Fy = F1 cos 30 + F2 cos 30 = (2.29 * 10-11 * cos 30) + (2.14 * 10-11 * cos 30) = 3.84 * 10-11

magnitude = sqrt [(7.5 * 10-13)2 + (3.84 * 10-11)2]

= 3.84 * 10-11 N

b) direction = tan-1 [3.84 * 10-11 / 7.5 * 10-13] = 88.88 + 180

= 268.8 deg

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