0.9812 0.9937 0.9749 0.9984 0.9874 Number of Question To Transcribe: 1008 Start

Question

0.9812 0.9937 0.9749 0.9984 0.9874 Number of Question To Transcribe: 1008 Start Transcription Rotate +90 Rotate -90 Question Id: 592129 00:9:15 Search Question: Go A mass spectrometer is used to separate two isotopes ofuranium with masses m1 andm2 where m2 >m1. The two types of uranium atom exit an ionsource S with the same charge of +e and are acceleratedthrough a potential difference V. The charged atoms thenenter a constant, uniform magnetic field B as shown. Ifr1 = 0.5049 m and r2 =0.5081 m, what is the value of the ratiom1/m2? a. 0.9812 b. 0.9937 c. 0.9749 d. 0.9984 e. 0.9874

Explanation / Answer

Shouldn't the answer be 0.9874?

Here's the work:

eV = 1/2 mv^2 (V=potential difference)
evB = mv^2/r (v=velocity and B=magnetic field)

thus m=(q^2B^2r^2)/(2V)

so m1/r1^2 = m2/r2^2 thus m1/m2 = .987 4

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