a 2kg ball is hanging from a string. the ball experiences constant acceleration

Question

a 2kg ball is hanging from a string. the ball experiences constant acceleration from an initial velocity of 9 m/s in the +x direction at t=0 s to 9m/s at an 38 degree angle above the +x axis at t=2.8s. what is x component of the balls final velocity? y component of final velocity? x component of balls acceleration? y component of balls acceleration? x component of tension force on ball? y component of tension force on ball? a 2kg ball is hanging from a string. the ball experiences constant acceleration from an initial velocity of 9 m/s in the +x direction at t=0 s to 9m/s at an 38 degree angle above the +x axis at t=2.8s. what is x component of the balls final velocity? y component of final velocity? x component of balls acceleration? y component of balls acceleration? x component of tension force on ball? y component of tension force on ball? a 2kg ball is hanging from a string. the ball experiences constant acceleration from an initial velocity of 9 m/s in the +x direction at t=0 s to 9m/s at an 38 degree angle above the +x axis at t=2.8s. what is x component of the balls final velocity? y component of final velocity? x component of balls acceleration? y component of balls acceleration? x component of tension force on ball? y component of tension force on ball?

Explanation / Answer

vfx = 9 cos38 = 7.09 m/s

vfy = 9 sin38 = 5.54 m/s

acceleration = (vf - vi) / t

= (7.09 - 9)i + (5.54j) / 2.8

= - 0.68i + 1.98j

a_x = - 0.68 m/s^2

a_y = 1.98 m/s^2

T_x = m a_x = 2 x -0.68 = - 1.36 N .....Ans

T_y = m(a_x + g) = 2(1.98 + 9.8) = 23.56 N ......Ans

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