. While bowling one day, you begin to wonder about the inertia of a bowling pin.
ID: 1656471 • Letter: #
Question
. While bowling one day, you begin to wonder about the inertia of a bowling pin. You know that balls and pins generally make elastic collisions and that your 6.5-kg bowling ball continues to move forward after a collision, even when you hit several pins to make a strike. As it happens, you have just managed to knock down nine of the ten pins, leaving only one pin upright at the end of the lane. You ask your friend to make a video of your next shot so that you can later carefully observe the initial and final velocities of your ball. Sure enough, you hit the remaining pin head-on (make the spare), and after a little video analysis you decide that your ball lost about 40% of its initial speed when it hit the pin.
answer is 1.6kg
Explanation / Answer
using law of conservation of linear momentum
v= final velocity of pin
V= initial velocity of bal
6.5V + m (0)= 6.5(0.6)V + mv
2.6V = mv -----------(1)
also in an elastic collision, relative velocitybefore separation= relative velocity after separation
V-0=v-0.6V
v= 1.6V
put the vaue of v in equation 1, we get
2.6V=m(1.6V)
m= 1.6 kg
so mass of pin= 1.6kg
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