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Problem What is the electric flux through a sphere that has a radius of 1.00 m a

ID: 1652919 • Letter: P

Question

Problem What is the electric flux through a sphere that has a radius of 1.00 m and carries a charge of +1.00µC at its center?

The magnitude of the electric field 1.00 m from this charge is found using Equation 23.9:

The field points radially outward and is therefore everywhere perpendicular to the surface of the sphere. The flux through the sphere (whose surface area A = 4 r2) is thus

Now consider a larger sphere of radius of 2.00 m instead. Comparing to that in the example, how has the electric flux changed?

2nd) 1.00 × 10-6 C E = 4,7 = (8.99 × 109 N . n2/C*) 1.00 × 10-6 C (1.00 m) N/C

Explanation / Answer

Electric field = kq/r^2

= 9 *10^9 * 10^-6 / 1^2

= 9000 N/C

electric flux = EF*Area

= 9000*4pi*1

= 113097.3 Nm^2 /C

Th electric flux would remain the same because according to gauss law electric flux = charge enclosed / permittivity of free space

and charge enclosed remains same here

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