A small uncharged conductor is brought near the electrostatic generator without

Question

A small uncharged conductor is brought near the electrostatic generator without touching it. What is the direction of the force acting on the small uncharged conductor? Explain why (one word explanation should be sufficient) The initially uncharged small conductor is now brought into a contact with the electroscope. As a result of the contact 0.3 moles of electrons are transferred between the electroscope and the small conductor. The charge on the generator is maintained at-30 mu C. What is the direction of the force acting on the small conductor now? What is the total charge on the small conductor now? What is magnitude of force acting on the small conductor?

Explanation / Answer

Initially you have solved the problems correctly.

I am solving only the last two questions.

Total charge on the small conductor = 0.3 moles of electrons = 0.3 x 6.022 x 10^23 electrons

now, 1 electron = -1.602 x 10^-19 C

So, total charge on the small conductor = 0.3 x 6.022 x 10^23x(-1.602 x 10^-19) C

= -2.89 x 10^4 C

Now for the force acting on the small conductor -

Distance between small conductor and electroscope, r = 0

Expression for the force, F = (k*q1*q2) / r^2

here, r = 0

So, F = infinity.

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.