A A wire of length 2.0 m long moves with a speed of 2.5 m/s perpendicular to a m

Question

A A wire of length 2.0 m long moves with a speed of 2.5 m/s perpendicular to a magnetic field (B) of

Exam 2d-1402-summer 2017- Word FILE HOME INSERT DESIGN PAGE LAYOUT REFERENCES MAILINGS REVIEW VIEW Jazmine Watts s Cut Find Helvetica Neu.-112-A. A. Aa- B 1 u. aic x, x' A... ·-·-·- Copy Paste :,-. INorrmal" No Spac Heading 1 Heading 2 Title Subtitle subtle Erm Emphasis Select- Editing Format Painter Font Paragraph Styles Navigation 0.0015 T. Calculate the generated electromotive force across the wire? Search document HEADINGS PAGES RESULTS Create an interactive outline of your document. It's a great way to keep track of where you are or quickly move your content around To get started, go to the Home tab and apply Heading styles to the headings in your document. PAGE 2 OF 6 266 WORDS E + 100% 1:43 PM O Type here to search 8/10/2017 2

Explanation / Answer

EMF generated in a moving wire of length L, and velocity V in a magnetic field B is given by

E = (V X BL) = VBLsin(theta) , here because the velocity is perpendicular to Magnetic field , we have theta = 90,

So E = (2.5 x 0.0015 x 2) = 0.0075 V = 7.5 mV is the EMF or Voltage generated across the wire.

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