(8c33p22) Radiation from the Sun reaching Earth (just outside the atmosphere) ha

Question

(8c33p22) Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1400 W/m2. What would the intensity be at Saturn? (See Appendix B, A-3) 7.1W/m^2 Submit Answer Incorrect. Tries 3/7 Previous Tries /H earth)/(distance to planet) Assuming that Earth (and its atmosphere) behaves like a flat disk perpendicular to the Sun's rays and that all the incident energy is absorbed, calculate the force on Earth due to radiation pressure. Submit Answer Tries 0/7 What would it be for Saturn? Submit Answer Tries 0/7 What is the force on the Earth due to the sun's gravitational attraction? Submit Answer Tries 0/7 What is it for Saturn? Submit Answer Tries 0/7

Explanation / Answer

Given,

Intensity, I = 1400W/m2

Surface area of earth, A = R2

where, R = 6400 km = 6400000 m

we know that radiation pressure if all the incident energy is absorbed is P = I/c

               P = 1400 / (3 x 108) = 466.67 x 10-8 N/m2

A) Force due to radiation, FR = P x A = (466.67 x 10-8) x x (6400000)2 = 6 x 108 N

B) Gravitational force due to the Sun, Fg = GMm/r2

where, G = 6.67 x 10-11Nm2/kg2, M = mass of sun = 2 x 1030 kg, m = mass of earth = 6 x 1024 kg, r =1.5 x 1011 m

Then, Fg = 6.67 x 10-11 x 2 x 1030 x 6 1024/(1.5 x 1011)2 = 35.57 x 1021 N

Above was regarding Earth, for Saturn, you didn't mention intensity (from appendix B). Follow the same procedure for Saturn respectively.

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