(8c23p20) The electric field just above the surface of the charged drum of a pho
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Question
(8c23p20) The electric field just above the surface of the charged drum of a photocopying machine has a magnitude E of 2.40x105 N/C What is the surface charge density of the drum, assuming that the drum is a conductor? Submit Answer Tries 0/7 (c24p16) (a) The drum of the photocopying machine in the problem above has a length of 48 cm and a diameter of 10 cm. What is the total charge on the drum? Submit Answer Tries o/7 The manufacturer wishes to produce a desktop version of the machine. This requires reducing the size of the drum to a length of 28 cm and a diameter of 6 cm. The electric field at the drum surface must remain unchanged. What must be the charge on this new drum? Submit Answer Tries 0/7Explanation / Answer
A) The Electric field above charge drum = E = 2.4* 10^ 5 N/c
surface chared density of chrged drum, ? = E ?
= (2.4*10^5)(8.854*10^-12) = 21.24 * 10^-7 C/m^2
B)
Radius = 5 cm =0.05 m
l = 2peor E
= 2 * 3.14 * 8.854 *10^-12* 0.05 * 2.4 * 10^5
= 6.68*10^-7
charge =l * length= 6.68* 10^-7 *0.48
= 3.20 * 10^-7 C
C)
E = 2.40×10^5 N/C
L = 0.28 m
R = 0.03 m
l = 2peor E
= 2 * 3.14 * 8.854 *10^-12* 0.03 * 2.4 * 10^5
= 4 *10^-7
charge =l * length
= 4 * 10^-7 *0.28
= 1.12 * 10^-7 C
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