A proton moving with a speed of 14 times 10^5 m/s perpendicular to a uniform mag

Question

A proton moving with a speed of 14 times 10^5 m/s perpendicular to a uniform magnetic field of 1.5 T will follow which of the paths described below (q_p = 1.6 times 10^-19 C and mp = 1.67 times 10^-27 kg) a circular path of 2.04 cm radius a straight line path a circular path of 0.974167 cm radius a circular path of 4.83 ? radius a circular path of 4.7586? radius A circular loop carrying a current of 1.5 A is oriented in a magnetic field of 10.5 T. The loop has an area of 0.142857 m^2, and is mounted on an axis, perpendicular to the magnetic field, which allows the loop to rotate. What is the torque on the loop when its plane is oriented at a 25 degree angle to the field? 3.125 N-m 0.67725 N-m 4.875 N-m 6.93 N-m 2.039 N-m

Explanation / Answer

According to the chegg guidelines I am allowed to answer only 1 question at a time.

1) r = mv/qB = (  1.67x10^-27* 14x10^5/(1.6x10^-19* 1.50 ) = 0.974166667 cm ( OPTION C) ===ANSWER)

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