please solve number 5.thank you (4) A proton is moving in a circular orbit of ra

Question

please solve number 5.thank you

(4) A proton is moving in a circular orbit of radius 10.0cm in a uniform 0.357 a circular orbit of radius 10.0cm in a uniform 0.351" magnetic field perpendicular to the vel a) The speed of the proton. b) The time it takes to complete one orbit. ocity of the proton. Find (5) Refer to the figure below: a) Find the equivalent resistance of the circuit. b) Find the current through R c) Find the potential difference across resistors 2 and 3 (½s). d) Find the current through R2 and R (6) Refer to the figure below: a) Find an equation relating the three currents at point b b) Find an equation relating the change in potentials around loop beb c) Find an equation relating the change in potentials around loop abcda d) Solve the system formed from these three equations to find currents /1, 12, and h 25 2-00

Explanation / Answer

5. (a)

From the figure,

R2 and R3 are parallel .

so, resultant resistance = 4*12 / (4 + 12) = 3 ohm

This is in series with R1.

so, resultant resistant of circuit = 3 + 5 = 8 ohm

(b)

Current in the circuit l = V / R

l = 16 / 8 = 2 A

current in the R1 = 2 A

(c)

potential diffrence b/w R2 and R3,

deltaV = V - l1R1 = 16 - (2*5)

deltaV = 6 V

(d)

Current through R2 and R3 will divide in opposite ration of resistance.

current through R2 = 12*2 / 16 = 1.5 A

current through R3 = 4*2 / 16 = 0.5 A

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