please solve all parts, if you cant then please dont solve it, also highlight th
ID: 778411 • Letter: P
Question
please solve all parts, if you cant then please dont solve it, also highlight the answer with suitable unit
itc as are b capacitor 2 capacitor 3, and d) capacitor 4? If bath s c The figure shows 11.2 V battery and four uncharged capacitors cf capacitar cas C 1.15 URG, 2.13 clozad, what is the charge on (a) capacitor L, (f) capacitor 2, (g) capacitor 3, and (h) capacitor 4 = 3.09 F and C1 = 4.19 I on s itch S closed, w hatthe charge on a capacitor 1 Units (o) Number (b) Number (c) Numbar| (d) Numbar () Numbar () Number (9) Number (h) Number Units units UnitsExplanation / Answer
when S1 is only closed
a)
charge on C1 = C13*V
= (C1*C3/(C1+C3))*V
= (1.15*3.09/(1.15 + 3.09))*11.2
= 9.39 micro C or 9.39*10^-6 C <<<<<<<-----Answer
b) charge on C2 = C24*V
= (C2*C4/(C2+C4))*V
= (2.13*4.19/(2.13 + 4.19))*11.2
= 15.8 micro C or 15.8*10^-6 C <<<<<<<-----Answer
c) charge on C3 = charge on C1 (since C1 and C3 are in series)
= 9.39 micro C or 9.39*10^-6 C <<<<<<<-----Answer
D)
charge on C2 = charge on C4 (since C2 and C4 are in series)
= 15.8 micro C or 15.8*10^-6 C <<<<<<<-----Answer
when S2 is also closed,
C12 = C1 + C2 = 1.15 + 2.13 = 3.28 micro F
C34 = C3 + C4 = 3.09 + 4.19 = 7.28 micro F
potential diffrence across C1 AND C2, V1 = V2 = C34*V/(C12 + C34)
= 7.28*11.2/(3.28 + 7.28)
= 7.72 V
potential diffrence across C3 AND C4, V3 = V4 = C12*V/(C12 + C34)
= 3.28*11.2/(3.28 + 7.28)
= 3.48 V
E) Q1 = C1*V1 = 1.15*7.72 = 8.88 micro F or 8.88*10^-6 C <<<<<<<-----Answer
F) Q2 = C2*V2 = 2.13*7.72 = 16.4 mciro F or 16.4*10^-6 F <<<<<<<-----Answer
G) Q3 = C3*V3 = 3.09*3.48 = 10.8 micro F or 10.8*10^-6 F <<<<<<<-----Answer
H) Q4 = C4*V4 = 4.19*3.48 = 14.6 micro F or 14.6*10^-6 F <<<<<<<-----Answer
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.