Two capacitors, one of capacitance C and the other of capacitance 2C are connect

Question

Two capacitors, one of capacitance C and the other of capacitance 2C are connected to an emf as shown below. Compare Q_1 the charge on the positive plate of capacitor C with Q_2 the charge on the positive plate of capacitor 2C. (a) Q_1 Q_2 In the circuit shown below, doubling the battery voltage will double the circuit's time constant. (a) True (b) False Three capacitors are connected to a battery as shown in the diagram. The potential difference provided by the battery is 24 volts, while C_1 = 8 mu F, C_2 = 6 mu F and C_3 = 4 mu F. What is Q_1, the charge on the capacitor C_1? What is U_total, the total energy stored in all of the capacitors? What is V_3, the potential difference across the plates of capacitor C_3?

Explanation / Answer

Solving first question of the page

5

As both capacitor are in parallel, voltage across both will be same. Charge=capacitance*voltage

Since 2C is greater than C so

Q2 is greater than Q1

Option (a) is correct

6

Time constant=RC so battery voltage does not have any effect so false

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