Two capacitors have equal capacitance. If the first capacitor is holding twice a
ID: 1588330 • Letter: T
Question
Two capacitors have equal capacitance. If the first capacitor is holding twice as much charge as the second capacitor, how do the capacitors’ voltages compare?
A. The first capacitor has four times the voltage as the second capacitor.
B. The first capacitor has the same voltage as the second capacitor.
C. The first capacitor has half the voltage as the second capacitor.
D. The first capacitor has twice the voltage as the second capacitor.
A. The first capacitor has four times the voltage as the second capacitor.
B. The first capacitor has the same voltage as the second capacitor.
C. The first capacitor has half the voltage as the second capacitor.
D. The first capacitor has twice the voltage as the second capacitor.
Explanation / Answer
Ans:If Q be the amount of charge in a capacitor of capacitance C then the voltage across it is V=Q/C;
So V1=Q1/C1 and V2 =Q2/C2 ; Now C2= C1 and Q1 =2* Q2
So, V1 = 2*Q2/C2= 2*V2
So the option D is correct.
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