Part A A heat engine carries 1 mole of an ideal gas around the following cycle:

Question

Part A A heat engine carries 1 mole of an ideal gas around the following cycle: Starting at a volume of 4.5 m3 and a temperature of 400K (point A), the gas expands isobarically to a final volume of 8 m (point B). Then, the gas is cooled down isochorically back down to its initial temperature (point C). The cycle is then completed with an isothermal process returning the gas to its original state (point A). The cycle is shown in the figure below.(Figure 1) Calculate QH for the cycle. Submit My Answers Give Up | Figure 1 of 1 Incorrect; One attempt remaining; Try Again Part B Calculate Qc for the cycle. Submit My Answers Give Up Incorrect; One attempt remaining; Try Again Part C Calculate the efficiency of the engine

Explanation / Answer

First we know all the three process and calculate all the properties

Process A-B = contant pressure process

Process B-C = constant volume process

Process C-A = Constant temperature process

Now At point A

Va = 4,5 m3 , Ta = 400 K

we know

PV = nRT

Pa x 4.5 = 1 x 8.314 x 400

Pa = 739.02 bar

Now At point B

Vb = 8 m3 , TB = ? , Pb = 739.02 bar

again

Pv = nRT

739.02 x 8 = 1 x 8.314 x Tb

Tb = 711.1 K

and point C

Vc = 8 m3 , Tc = 400k

hence

PV = nRT

p x 8 = 1 x 8.314 x 400

Pc = 415.7 bar

Part (A)

QH = Cv (Tb - Ta)

= 20.785 (711.1 - 400)

= 6466.21 J

Like this you can easily use data to caculate all details

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